(3x^2+4)(2x^2-3)+4x(3x-5)=

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Solution for (3x^2+4)(2x^2-3)+4x(3x-5)= equation: 


Simplifying
(3x2 + 4)(2x2 + -3) + 4x(3x + -5) = 0

Reorder the terms:
(4 + 3x2)(2x2 + -3) + 4x(3x + -5) = 0

Reorder the terms:
(4 + 3x2)(-3 + 2x2) + 4x(3x + -5) = 0

Multiply (4 + 3x2) * (-3 + 2x2)
(4(-3 + 2x2) + 3x2 * (-3 + 2x2)) + 4x(3x + -5) = 0
((-3 * 4 + 2x2 * 4) + 3x2 * (-3 + 2x2)) + 4x(3x + -5) = 0
((-12 + 8x2) + 3x2 * (-3 + 2x2)) + 4x(3x + -5) = 0
(-12 + 8x2 + (-3 * 3x2 + 2x2 * 3x2)) + 4x(3x + -5) = 0
(-12 + 8x2 + (-9x2 + 6x4)) + 4x(3x + -5) = 0

Combine like terms: 8x2 + -9x2 = -1x2
(-12 + -1x2 + 6x4) + 4x(3x + -5) = 0

Reorder the terms:
-12 + -1x2 + 6x4 + 4x(-5 + 3x) = 0
-12 + -1x2 + 6x4 + (-5 * 4x + 3x * 4x) = 0
-12 + -1x2 + 6x4 + (-20x + 12x2) = 0

Reorder the terms:
-12 + -20x + -1x2 + 12x2 + 6x4 = 0

Combine like terms: -1x2 + 12x2 = 11x2
-12 + -20x + 11x2 + 6x4 = 0

Solving
-12 + -20x + 11x2 + 6x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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